Question

please give me the correct answer ​

Answer 1

Answer:

(i) OB = OC

Step-by-step explanation:

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Answer 2

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i) OB = OC

in ∆ABC

AB = BC

➪ ∠B = ∠C ( angle opposite to equal sides are equal)

➪ 1/2 ∠B = 1/2 ∠C

➪ ∠OBC = ∠OCB....(i)

and ∠ABO = ∠ACO .......(ii)

( OB and OC are bisectors of ∠B and ∠C respectively)

now, in ∆OBC

∠OBC = ∠OCB [from (i)]

➪ OB = OC.....(iii) ( sides opposite to equal angles are equal)

________________________

ii) AO bisect ∠A

in ∆AOB and ∆AOC

• AB = AC (given)
• OB = OC [proved above in (iii)]
• AO = AO (common)

so by SSS congruency rule ∆AOB ≅ ∆AOC

now, ∠BAO = ∠CAO (by C.P.C.T)

then, we can say that AO bisect ∠A