Question

please give me the correct answer​

Answer 1

Answer:

${x}^{3} - {x}^{2} - 1 - (2 {x}^{3} + 3 {x}^{2} - 5x + 6) \\ = {x}^{3} - {x}^{2} - 1 - 2 {x}^{3} - 3 {x}^{2} + 5x - 6 \\ \\ { \boxed{ \red{= - {x}^{3} - 4 {x}^{2} + 5x - 7}}}$

Answer 2

${x}^{3} - {x}^{2} - 1 - (2 {x}^{3} + 3 {x}^{2} - 5x + 6)$

${x}^{3} - {x}^{2} - 1 - 2 {x}^{3} - 3 {x}^{2} + 5x - 6$

$= - {x}^{3} - 4 {x}^{2} + 5x - 7$

By $- {x}^{3} - 4 {x}^{2} + 5x - 7$ (this much) $2 {x}^{3} + 3 {x}^{2} - 5x + 6$ exceed ${x}^{3} - {x}^{2} - 1$