Question

please give me the correct answer ​

Answer 1

malyali ano nyan aakakakwka

Answer 2

Given,

Distance between two objects of a given mass is halved.

To find,

What will be the change in force of attraction between them?

Solution,

Let, mass of two objects = M1 and M2

Distance = d

Gravitational acceleration = G

So,

Force of attraction = F = (G × M1 × M2)/d²

Now, distance is halved = d/2

Force of attraction = (G× M1 × M2)/(d/2)² = 4 × (G × M1 × M2)/d²

Hence, the force of attraction will be increased by four times.

________________________________________________

Given,

The data set is attached in the given diagram.

To find,

The values of the missing data.

Solution,

Data (I) :

M1 = 12 kg , M2 = 5 kg , d = 2m

F = G × (12×2)/(2)² = G × 24/4 = G×6

So, Data (I) = 6

Data (II) :

M1 = 50 kg , M2 = x kg , d = 5m

Now,

F = G × 40

or, F = G × M1×M2/d²

So, M1×M2/d² = 40

50 × x /(5)² = 40

50 × x/25 = 40

2x = 40

x = 20

So, data (II) = 20

Data (III)

M1 = x kg , M2 = 15 kg , d = 0.5

Now, F = G×400

or, F = G × M1×M2/d²

So,

M1×M2/d² = 600

x×15/(0.5)² = 600

x×15/0.25 = 600

x × 60 = 600

x = 10

So, data(III) = 10

Hence, three missing data (I,II,II) are 6,20,10 respectively.