Question

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Answer 1

Answer:

1). 5 + X = 9

X = 9- 5

X = 4

2) m/ 2 = 1

m = 1 × 2

m = 2

3). 2x + 8

2 ( -2) + 8

= -4 + 8

= 4

4). 4( X + 2) = 2x + 18

= 4x + 8 = 2x + 18

4x - 2x = 18- 8

2x = 10

X = 10/ 2

X = 5

5). 10 - 3x = -2

- 3x = -2 - 10

-3x = -12

X = -12/ -3

X = 4

6). 3x - 1 = 11

3x = 11+ 1

3x = 12

X = 12/3

X = 4

7). X + 6 = 16

X = 16- 6

X = 10

8). 2x - 1 = 9

X = 5

2 ( 5) - 1 = 9

10- 1 = 9

9 = 9

9). let the cost of a pen is = 2x

let the cost of eraser is = X

2x + X = 39

3x = 39

X = 39/3

X = 13

cost of eraser is = 13

cost of pen is = 13× 2 = 26

Answer 2

Answer:

1. $5 + x = 9$

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2. $m = 2$

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3. $2x + 8 = 4$

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4. $x = \frac{1}{2}$

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5. $10 - 3x = - 2 \\ \\ - 3x + 10 = - 2 \\ \\ - 3x + 10 - 10 = - 2 - 10 \\ \\ - 3x = - 12 \\ \\ \frac{ - 3x}{ - 3} = \frac{ - 12}{ - 3} \\ \\ x = 4$

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6. $3x - 1 = 11 \\ \\ 3x - 1 + 1 = 11 + 1 \\ \\ 3x = 12 \\ \\ \frac{3x}{3} = \frac{12}{3} \\ \\ x = 4$

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7. $x + 6 = 16$

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8. $2x - 1 = 9 \\ \\ 2x - 1 + 1 = 9 + 1 \\ \\ 2x = 10 \\ \\ \frac{2x}{2} = \frac{10}{2} \\ \\ x = 5$

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9. Let pen=p

Eraser=e

$p = 2e \\ \\ p + e = 39 \\ \\ 2e + e = 39 \\ \\ 3e = 39 \\ \\ e = \frac{39}{3} \\ \\ e = 13 \\ \\ p = 2e \\ \\ p = 2(13) \\ \\ p = 26 \\ \\ ∴cost \: of \: pen = 26 \: and \: cost \: of \: eraser = 13$

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