please give me the correct answer for brainly answer
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Step-by-step explanation:
(2^3y-1+10)÷7 = 6
2^3y-1 + 10 = 6×7
2^3y-1+ 10 = 42
2^3y-1= 42 -10
2^3y-1= 32
2^3y/2 = 32
2^3y =32×2
2^3y = 64
2^6 = 64
so 3y = 6
y =2
Answered by
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Question;
If {2^(3y-1) + 10}÷7 = 6 , then y =?
Solution:
We have;
=> {2^(3y-1) + 10}÷7 = 6
=> {2^(3y-1) + 10}/7 = 6
=> {2^(3y-1) + 10} = 6×7
=> {2^(3y-1) + 10} = 42
=> 2^(3y-1) = 42 - 10
=> 2^(3y-1) = 32
=> 2^(3y-1) = 2^5
=> 3y - 1 = 5
=> 3y = 5 + 1
=> 2y = 6
=> y = 6/2
=> y = 3
Hence, the required value of y is 3.
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