Math, asked by DevilAK666, 10 months ago

please give me the correct answer for brainly answer​

Attachments:

Answers

Answered by MERILL
1

Step-by-step explanation:

(2^3y-1+10)÷7 = 6

2^3y-1 + 10 = 6×7

2^3y-1+ 10 = 42

2^3y-1= 42 -10

2^3y-1= 32

2^3y/2 = 32

2^3y =32×2

2^3y = 64

2^6 = 64

so 3y = 6

y =2

Answered by Anonymous
1

Question;

If {2^(3y-1) + 10}÷7 = 6 , then y =?

Solution:

We have;

=> {2^(3y-1) + 10}÷7 = 6

=> {2^(3y-1) + 10}/7 = 6

=> {2^(3y-1) + 10} = 6×7

=> {2^(3y-1) + 10} = 42

=> 2^(3y-1) = 42 - 10

=> 2^(3y-1) = 32

=> 2^(3y-1) = 2^5

=> 3y - 1 = 5

=> 3y = 5 + 1

=> 2y = 6

=> y = 6/2

=> y = 3

Hence, the required value of y is 3.

Similar questions