Question

Please give me the correct answer of q.no.4 (b) I make u as brainleast guys please​

Answer 1

x/3 - 1/3 -x/4 + 1/2 = 1

rearranging the terms

x/3 - x/4 -1/3 +1/2 =1

x/12 + 1/6 = 1

(x+2)/12 = 1

x+2=12

x=12-2

x=10

hope it helps

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Answer 2

Given:

• A linear equⁿ is given to us.
• The equⁿ is $\sf{\dfrac{1}{3}(x-1)-\dfrac{1}{4}(x-2)=1.}$

To Find:

• The value of x .

Answer:

Let us take the given equⁿ:-

$\sf{\implies \dfrac{1}{3}(x-1)-\dfrac{1}{4}(x-2)=1 .}$

$\sf{\implies \dfrac{x}{3}-\dfrac{1}{3}-\dfrac{x}{4}+\dfrac{2}{4}=1 .}$

( Opening the brackets )

$\sf{\implies \dfrac{x}{3}-\dfrac{x}{4}-\dfrac{1}{3}+\dfrac{1}{2}=1.}$

(Grouping constant terms and variables .)

$\sf{\implies \dfrac{4x-3x}{12}+\dfrac{-2+3}{6}=1.}$

$\sf{\implies \dfrac{x}{12}+\dfrac{1}{6}=1 .}$

$\sf{\implies \dfrac{x+2}{12}=1.}$

$\sf{\implies x+2 = 12.}$

$\sf{\implies x = 12-2.}$

$\bf{\implies x=10.}$

Hence the value of x is 10.