Question

please give me the correct solution

chapter:- mensuration​

Answer 1

Answer:

Mensuration,

We have

Polygon ABCDE

Have to find the area of the polygon.

Here given that

AC = 60 m BG = 16 m

AF = 16 m

So FH will be (46 - 16) m = 30 m and HC will be (60-46) m = 14 m also,DH = 14 m

FE = 24 m

Now,

Area of the polygon = area of AABC + area of ACHD + area of AAFE + area of trapezium DEFH.

[(2 x 60 x 16) + (1/2 × 14 ×14) + (1/2 x 16 x 24) + (2x30x (24+14))] m²

(480 +98 + 192 + 570) m²

= 1340 m²

So the area of the polygon is 1340 m²

That's it

Hope it helped

(Öv Ö.)

Answer 2

Step-by-step explanation:

we know, area of triangle

→ ½ × height × base

area of triangle ∆ABC

Height = 16

base = 60

area = ½ × 16 × 60 → 8 × 60 → 420 cm²

area of triangle ∆AFE

height = 24 cm

base = 16 cm

area = ½ × 24 × 16 → 24 × 8 → 192 cm²

area of quadrilateral, we can divide it in two shapes right triangle and square

area of right triangle → ½ × height × base

→ ½ × 14 × 16 → 14 × 8 → 112 cm²

and area of square → a × a → 14 × 14 → 196cm²

so are of quadrilateral FHDE → 112 + 196 → 308 cm²

area of ∆DHC

height = 14

base = 60 - 46 = 14

area = ½ × 14 × 14 → 196/2 = 98 cm²

So area of polygon will be

→ ∆ABC + ∆AFE + FHDE + ∆DHC

→ 420 + 192 + 308 + 98

→ 1018 cm²

therefore, required area of given polynomial is 1018cm².

hope this answer helps you dear...!