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Answers
Answer:
Step-by-step explanation:
Given
Principal (P) = Rs 40000
Amount (A) = Rs 46305
Period (n) = 1 2/ 1
years = 3/2 years
So half yearly, 2n = 2 × (3/2) = 3 years.
Let the rate of interest be r% p.a.
A / P = (1 + r / 100)
n
46305 / 40000 = (1 + r / 100)
3
(1 + r / 100)
3
= 46305 / 40000
On further calculation, we get,
(1 + r / 100) 3
= 9261 / 8000
(1 + r / 100) 3
= (21 / 20) 3
We get,
(1 + r / 100) = (21 / 20)
r / 100 = (21 / 20) – 1
r / 100 = 1 / 20
r = 100 / 20
We get,
r = 5
Therefore, rate of interest = 5% for half year.
So, 2 × 5 = 10% per annum.
Answer:
10 ans
Amount = 2315.25
Time = 3 years and principal = 2000
Amount = P(1+ r/100)™
2315.25 = 2000(1+ r/100)3
2315.25/2000 = (1+r/100)3
9261/8000 = (1+r/100)power 3
Cube root 9261/8000 = 1+ r/100
21/20 = 1 + r/ 100
Now take the l.c.m. of 100 and cross multiply it by 21
2100/20 = 100 + r
105 = 100 + r
R = 5%
11 ans
Given
Principal (P) = Rs 40000
Amount (A) = Rs 46305
Period (n) =1 1 = 3/2 years
2
years = 3/2 years
So half yearly, 2n = 2 × (3/2) = 3 years.
Let the rate of interest be r% p.a.
WKT
A / P = (1 + r / 100)n
46305 / 40000 = (1 + r / 100)3
(1 + r / 100)3 = 46305 / 40000
On further calculation, we get,
(1 + r / 100)3 = 9261 / 8000
(1 + r / 100)3 = (21 / 20)3
We get,
(1 + r / 100) = (21 / 20)
r / 100 = (21 / 20) – 1
r / 100 = 1 / 20
r = 100 / 20
We get,
r = 5
Therefore, the rate of interest = 5% for half a year.
So, 2 × 5 = 10% per annum
12 ans
It is given that
Amount (A)=17576
Principal (P)=15625
Rate =4% p.a.
Consider n years as the period
We know that
A/P = (1+r/100)
n
Substituting the values
17576/15625=(1+4/100)
n
By further calculation
(26/25)
3
=(26/25)
n
So we get
n=3
13 ans
Principal (P) = Rs. 16000
Rate of interest = 10 %
⇒ 10/2 = 5 % compounded semi annually
Amount (A) = Rs. 18522
Let the number of six monthly period be 'n'
A = P(1 + R/100)ⁿ
⇒ 18522 = 16000(1 + 10/100)ⁿ
⇒ 18522/16000 = [(20 + 1)/20]ⁿ
⇒ 9261/8000 = (21/20)ⁿ
⇒ (21*21*21)/(20*20*20) = (21/20)ⁿ
⇒ (21/20)³ = (21/20)ⁿ
⇒ n = 3
Three periods of 6 months = 1 1/2 years.