please give me the one solution from both of them.
Attachments:
Answers
Answered by
1
sin^3ø -cos^3ø= (sinø-cosø)(sin^2ø +cos^2ø + sinøcosø)
by using this identity
sin^3ø -cos^3ø/sinø -cosø=sin^2ø +cos^2ø + sinøcosø..........(i)
and sin^3ø + cos^3ø/sinø + cosø=sin^2ø +cos^2ø - sinøcosø........(ii)
by adding (i) and(ii)we get our required ans
sin^2ø +cos^2ø + sin^2ø +cos^2ø =2
by using this identity
sin^3ø -cos^3ø/sinø -cosø=sin^2ø +cos^2ø + sinøcosø..........(i)
and sin^3ø + cos^3ø/sinø + cosø=sin^2ø +cos^2ø - sinøcosø........(ii)
by adding (i) and(ii)we get our required ans
sin^2ø +cos^2ø + sin^2ø +cos^2ø =2
Similar questions