Question

please give me the one solution from both of them.

Answer 1

sin^3ø -cos^3ø= (sinø-cosø)(sin^2ø +cos^2ø + sinøcosø)
by using this identity
sin^3ø -cos^3ø/sinø -cosø=sin^2ø +cos^2ø + sinøcosø..........(i)
and sin^3ø + cos^3ø/sinø + cosø=sin^2ø +cos^2ø - sinøcosø........(ii)
by adding (i) and(ii)we get our required ans

sin^2ø +cos^2ø + sin^2ø +cos^2ø =2