Please give me the perfect derivation for 2nd and 3rd law of motion.
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Statement-The rate of change of momentum is directly proportional to the force applied on the body and takes place in the direction of the force applied.
Explanation-This law quantifies force it tells us how to measure force in terms of other known quantities which we can measure .
Derivations-Consider a body of mass m moving with initial u .Let a force F acts on the body for time t so that the velocity of the body after time t is v.
Initial momentum of the body pi=mu
Final " " " " pf=mv
Now, change in momentum of the body =p=pf-pi
=mv-mu=m(v-u)
Time taken to change this momentum =(t-0)=t
Rate of change of momentum =change of momentum / Time taken
= m(v-u)/t
According to the definition of newton*s second law of motion
Force applied ∞ rate of change of momentum
or F∞m(v-u)/t
Since v=u+at or (v-u/t)=a
Therefore, eqn. (i) can be written as
F∞ma
or F=k ma ...(ii)
where K is constant of proportionality
If F=1 unit
m=1 unit
a=1 unit
Then from eqn.(ii),1=K
Put this value of K =1 eqm.(ii),we get
F=ma
Explanation-This law quantifies force it tells us how to measure force in terms of other known quantities which we can measure .
Derivations-Consider a body of mass m moving with initial u .Let a force F acts on the body for time t so that the velocity of the body after time t is v.
Initial momentum of the body pi=mu
Final " " " " pf=mv
Now, change in momentum of the body =p=pf-pi
=mv-mu=m(v-u)
Time taken to change this momentum =(t-0)=t
Rate of change of momentum =change of momentum / Time taken
= m(v-u)/t
According to the definition of newton*s second law of motion
Force applied ∞ rate of change of momentum
or F∞m(v-u)/t
Since v=u+at or (v-u/t)=a
Therefore, eqn. (i) can be written as
F∞ma
or F=k ma ...(ii)
where K is constant of proportionality
If F=1 unit
m=1 unit
a=1 unit
Then from eqn.(ii),1=K
Put this value of K =1 eqm.(ii),we get
F=ma
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