Question

Please, give me the proof of this theorem.

Detail

Theorem 7.2: Angle opposite to equal sides of an isosceles triangle are equal.

please don't give wrong answer

if you give right answer with explanation i will makes you brainliest and follow you.

Answer 1

Step-by-step explanation:

ABC is a given triangle with, AB=AC.

To prove: Angle opposite to AB= Angle

opposite to AC (i.e) ∠C=∠B

Construction: Draw AD perpendicular to BC

∴∠ADB=∠ADC=90

o

Proof:

Consider △ABD and △ACD

AD is common

AB=AC

∴∠ADB=∠ADC=90

o

Hence ∠ABD=∠ACD

∠ABC=∠ACB

∠B=∠C. Hence the proof

This is known as Isosceles triangle theorem

Answer 2

Step-by-step explanation:

Here is the 7.2 theorem of maths std 9