Please give me the right answer yr.. it's very important so don't spam... it's study time now..
Attachments:
Answers
Answered by
3
Answer=152 cm^2
solution,
ABCD is a trapezium in which AB = 25 cm , CD= 13cm ( AB | | CD ) , and BC=AD = 10 cm. , draw perpendiculars CP and DQ from C and D on AB.
- PB = QA as BC = AD. =10 cm. Let PB =QA = x cm.
- AB = QA+QP+PB. , putting AB=25 cm., PB= QA=x cm. , and QP = CD=13 cm.
- 25= x +13+x. => 2x= 25–13 =>. x=12/2= 6 cm.
In right angled triangle CPB , CP^2+PB^2 = BC^2.
- or. CP^2 + 6^2 = 10^2.
- or. CP^2 = 100 -36 =64.
- or. CP = 8 cm.
Area of trapezium ABCD = 1/2.(AB+CD)×CP = 1/2.(25+13)×8. cm^2.
= 1/2.(38×8) = 152 cm^2.
Similar questions