Math, asked by itzsweety90, 4 months ago

Please give me the right answer yr.. it's very important so don't spam... it's study time now..​

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Answers

Answered by btsarmyforever90
3

Answer=152 cm^2

solution,

ABCD is a trapezium in which AB = 25 cm , CD= 13cm ( AB | | CD ) , and BC=AD = 10 cm. , draw perpendiculars CP and DQ from C and D on AB.

  • PB = QA as BC = AD. =10 cm. Let PB =QA = x cm.

  • AB = QA+QP+PB. , putting AB=25 cm., PB= QA=x cm. , and QP = CD=13 cm.

  • 25= x +13+x. => 2x= 25–13 =>. x=12/2= 6 cm.

In right angled triangle CPB , CP^2+PB^2 = BC^2.

  1. or. CP^2 + 6^2 = 10^2.

  1. or. CP^2 = 100 -36 =64.

  1. or. CP = 8 cm.

Area of trapezium ABCD = 1/2.(AB+CD)×CP = 1/2.(25+13)×8. cm^2.

= 1/2.(38×8) = 152 cm^2.

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