Question

Please give me the solution ​

Answer 1

the coach buy 3 bats and 6 balls at price. is 3900

then buy a bat and 2 balls at price is 1300

algebraically

1 ×3 = 3 bat and 2×3 =6 balls at price is 1300×3 = 3900

Answer 2

we need to form linear equation for the situation.

let cost of one ball = ₹x

let cost of one bat = ₹y

In first case,three bats and 6 balls cost him 3900₹ therefore our equation becomes

= 3x +6y =3900_________(1)

dividing equation by 3 both side

=x +2y =1300

x =1300 - 2y

for plotting the equation of graph, take different value of x from equation or you can do vice versaAt y =0= = x= 1300 -2(0) = x =1300 now finding the value at x = 0

0 = 1300-2y

2y = 1300

y = 650

in second case he buys one bat and 3 balls for 1300 therefore,

= x +2y = 1300_________(2)

x=1300 -2y

At y =0

x=1300 -2(0)

x= 1300

x =0

0=1300-2y

2y=1300

y=650