Question

please give me the solution
anybody have solution? ​

Answer 1

Explanation:

Let R and r be the radii of the top and base of the bucket respectively, Let h be its height. Then, we have R = 20 cm, r = 10 cm, h = 30 cm Capacity of the bucket = Volume of the frustum of the cone = 1/3 π(R2 + r2 + R r )h = 1/3 π(202 + 102 + 20 x 10 ) x 30 = 3.14 x 10 (400 + 100 + 200) = 21980 cm3 = 21.98

Answer 2

h=30cm

r=10cm

r'=20cm

volume of bucket=1/3×π×h×(r^2+r'^2+r×r')

=1/3×22/7×30×(10^2+20^2+10×20)

=1/3×22/7×30×700

=22000cm^3 answee