Question

please give me the solution for this ​

Answer 1

Answer:

8

Step-by-step explanation:

given

a^3+b^3+c^3=28

ac= 4/b

abc=4

(1/a+1/b+1/c)

by taking lcm

=(ab+bc+ca)/abc= 0(abc=4)

(so abc#0)

=> ab+bc+ca=0

a+b+c=2

from the below identity

a^3+b^3+c^3 -3abc= (a+b+c)(a^2+b^2+c^2-ab-bc-ca)

28-3*4= 2*(a^2+b^2+c^2-(ab+bc+ca))

28-12=2*(a^2+b^2+c^2-0)

16/2= a^2+b^2+c^2

a^2+b^2+c^2=8