Question

Please give me the solution of q9 with all 4 solution why pythagorean or why not??BRAINLIEST QUESTION 15 pts

Answer 1

STEP BY STEP EXPLANATION :

General information :

( For when the first term is odd :

A given set is pythagorean in case the first digit is the smallest among all the three and the sum of the other two is equal to the square of the first digit as well as the difference of the 2nd and the 3rd term equals 1.

For when the first term is even :

A given set is pythagorean in case the first digit is the smallest among all the three and the square of the first term when divided by two equals the sum of 2nd and 3 rd term as well as the difference of the 2nd and the 3rd term equals 2. )

1. SET A (3 , 4, 5 )

In set A ,

The first digit is the smallest and is an odd number .

Thus ,

Sum of 2nd amd 3rd term = 9

I.e. 4 + 5 = 9

And ,

On squaring the first digit

I.e. 3² = 9

Now ,

The difference between 4 and 5 is 1

Hence , set 1 is a pythagorean set .

2. SET B ( 6 , 7 , 8 )

Now , since first term is even .

Then ,

Sum of 3rd and 2nd digit

I.e. 7 +8 = 15

And ,

Sum = first digit ²/2

I.e. 12² /2 = 72

Thus , the given set is not pythagorean .

3. SET C ( 10 , 24 , 26 )

1st term = 10

2nd term = 24

3rd term =26

Sum of 2nd and 3 rd term = 50

Square of 1 st term when divided by two equals 50 .

Thus , the set holds true for 1 st condition .

Checking the other condition ;

Difference between 3 rd and 2 nd term = 2 .

Thus , the given set is pythagorean.

4. SET D ( 2 , 3 , 4 )

1st term = 2

2nd term = 3

3 rd term = 4

Sum of 2 nd and 3 rd term = 7

Square of 1st term = 4

On diving the square of 1st term by 2 we get 2

Thus , the given set is not pythagorean .