Question

please give me the solution of the sum​

Answer 1

Step-by-step explanation:

2/3x3-x2+1/3=t2

then,

2x2-2xdx=2tdt

2(x2-x)dx=2tdt

x2-xdx=tdt

dx=tdt÷{x2-x}

integ ((1÷t)tdt)÷x2-x)

integ(1÷{x2-x})dt

sorry it's half solved

Answer 2

Answer:

idk sry.............................................