Question

please give me the solution of this question​

Answer 1

Answer:

ur answer is in this attachment please kindly refer to the attachment and please mark me as brainlist and pls follow me dear

Answer 2

Answer:

$\frac{sin5A\ - sin7A\ + sin5A\ - sin4A}{cos4A\ + cos7A\ - cos5A\ - cos5A}\ = cot6A$

⇒$\frac{sin\frac{5A}{7A}\ + sin\frac{5A}{4A}}{cos4A*7A\ - cos\frac{5A}{8A}}\ = cot6A$

$\frac{sin\frac{5}{7}\ + sin\frac{5}{4}}{cos28A^{2}\ + cos\frac{5}{8}}\ = cot6A$

$\frac{sin\frac{5}{7}*\frac{5}{4}}{cos28A^{2}*\frac{5}{8}}\ = cot6A$

$\frac{sin\frac{25}{28}{cos\frac{35A^{2}}{2}}\ = \frac{cos6A}{sin}$

$sin\frac{25}{28}*sin\ = cos\frac{35A^{2}}{2}*cos6A$

$sin^{2}\frac{25}{28}\ = cos^{2}\frac{210A^{3}}{2}$

Step-by-step explanation: