Math, asked by itzjkisok, 19 days ago

please give me the solution of this question, it's urgent​

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Answers

Answered by BrainlyPheonix
16

Answer:

5 \times    {10}^{ - 7} m

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Answered by мααɴѕí
4

Answer:

Let the enlargement factor of the bacteria be x and the enlarged length of the bacteria be y.

The number of times the bacteria enlarges is directly proportional to the length attained.

Two numbers x and y are said in direct proportion if, the relationship between two quantities is such that if we increase one, the other will also increase, and if we decrease one the other quantity will also decrease.

x/y = k, x = ky

where k is a constant.

Thus, x₁ / y₁ = x₂ / y₂

x₂ / y₂ = x₁ / y₁

y₂ = (20000 × 5) / 50000

y₂ = 2

Thus, the enlarged length will be 2 cm.

Now, to calculate the actual length we know that the enlargement factor will be 1. Let the actual length be l

Using x₁ / y₁ = x₂ / y₂

50000 / 5 = 1 / l

l = 5 / 50000

l = 10-4

Thus, the actual length of the bacteria is 0.0001 cm.

Step-by-step explanation:

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