Question

Please give me the solution to this question.

Answer 1

Answer:

$a. \: \: {2}^{x + 1} - {2}^{x - 1} = 15 \\ {2}^{x} \times 2 - {2}^{x} \times \frac{1}{2} = 15 \\ {2}^{x} (2 - \frac{1}{2} ) = 15$

a. Yes we can write.

b.

${2}^{x} (2 - \frac{1}{2} ) = 15 \\ {2}^{x} \binom{4 - 1}{2} = 15 \\ {2}^{x} \times \frac{3}{2} = 15 \\ {2}^{x} = \frac{15 \times 2}{3} \\ {2}^{x} = 10$