please give me the steps of a construction of a triangle ABC in which BC=7cm , angle B = 75° and AB+AC= 13cm
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Draw BC 7 cm
At b make an angle of 75°.
Mark the ray bx
Cut an arc of 13 cm from B to D
join DC
draw pq perpendicular to BC
let it intersect be at A
join DC
we got ABC the required triangle.
At b make an angle of 75°.
Mark the ray bx
Cut an arc of 13 cm from B to D
join DC
draw pq perpendicular to BC
let it intersect be at A
join DC
we got ABC the required triangle.
Shivangiiii:
Thank you so much
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