Question

please give me this answer​

Answer 1

Answer:

as PR is the bisector of angle APQ so angle APR=RPQ. as APQ+DPQ=180 degree so angle RPQ= 180-110=70/2=35 similarly RQP=70/2=35 .so angle x=110

Answer 2

Answer:

x= 110°

Step-by-step explanation:

BPQ=DQP=110°(angles on the same side of a transversal are always equal.)

APQ+BQP=180°

APQ+110°=180°

APQ=180°-110°

APQ=70°

similarly,CQP=70°

APQ is bisected by PR

RPQ=APQ/2

RPQ=70°/2

RPQ=35°

similarly,RQP=35°

In ∆RPQ, sum of all the angles are 180°

RPQ+RQP+QPR=180°

35°+35°+QRP=180°

QRP=180°-70°

QRP=110°

QRP=x (vertically opposite angles)

x=110°