Question

Please give me this answer correctly ​

Answer 1

Answer:

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Step-by-step explanation:

$[[{(\frac{-3}{4} )^{-2}}]^{-3} ]^{-1}$

first lets take and solve $(\frac{-3}{4} )^{-2}$

$(\frac{-3}{4} )^{-2}$ = $(\frac{4}{-3})^{2}$                [∵ $(\frac{a}{b} )^{-m} = (\frac{b}{a} )^{m}$]

⇒ $(\frac{4}{-3})^{2}$  = $(\frac{4^{2}}{-3^{2}} )$             [∵ $(\frac{a}{b} )^{m} = (\frac{a^{m}}{b^{m}} )$]

⇒ $(\frac{4^{2}}{-3^{2}} )$ = $\frac{16}{9}$                   [∵ $-a^{2} = -a$ x $-a$ ]  [∵ -a x -a = a ]

⇒$\frac{16}{9}$  

Now,

$(\frac{16}{9})^{-3}$ = $(\frac{9}{16})^{3}$                    [∵ $(\frac{a}{b} )^{-m} = (\frac{b}{a} )^{m}$]

⇒$(\frac{9}{16})^{3}$ = $(\frac{9^{3}}{16^{3}})$                       [∵ $(\frac{a}{b} )^{m} = (\frac{a^{m}}{b^{m}} )$]

⇒ $(\frac{9^{3}}{16^{3}})$= $\frac{729}{4096}$                      [∵ $a^{3} = a$ x $a$ x $a$]

then,

$(\frac{729}{4096})^{-1}$ = $(\frac{4096}{729})^{1}$              [∵ $(\frac{a}{b} )^{-m} = (\frac{b}{a} )^{m}$]

$(\frac{4096}{729})^{1}$  = $\frac{4096}{729}$                    [∵ a^1 = a ]

now,

$\frac{4096}{729}$  = 5.61865

pls mark as brainiest i have taken my time to answer this pls mark as brainliest pls :)