Question

please give me this answer
$if cos {}^{2}x\ \:\pi \div 6 = 2 \: find \: x$
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Answer 1

Answer:

LHS=cos2x+cos2(x+3π)+cos2(x−3π)Weknowthat,cos2x=2cos2x−1∴cos2x=2cos2x+1∴cos2(x+3π)=2cos2(x+3π)+1∴cos2(x−3π)=2cos2(x−3π)+1∴LHS=1+2cos2x+21+cos(2x+32π)+21+cos

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