Question

please give me this question answer​

Answer 1

Answer:

Step-by-step explanation:

$(\frac{11}{9} )^3 \times (\frac{11}{9} )^6=(\frac{11}{9} )^{2x-1}\\\\(\frac{11}{9} )^{3+6} =(\frac{11}{9} )^{2x-1}\\\\\\So \ 9=2x-1\\\\2x=9+1=10\\\\x=\frac{10}{2}\\\\\bf x=5$

Answer 2

Given : $\sf{Expression:\bigg(\dfrac{11}{9}\bigg)^{3} × \bigg(\dfrac{11}{9}\bigg)^{6}=\bigg(\dfrac{11}{9}\bigg)^{2x-1}}\:$

Need To Find : The Value of x .

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$\bigstar\sf{ \bigg(\dfrac{11}{9}\bigg)^{3} × \bigg(\dfrac{11}{9}\bigg)^{6}=\bigg(\dfrac{11}{9}\bigg)^{2x-1}}\:\:$

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Solving \: the \: Given \: Expression \::}}$

$:\implies \sf{ \bigg(\dfrac{11}{9}\bigg)^{3} × \bigg(\dfrac{11}{9}\bigg)^{6}=\bigg(\dfrac{11}{9}\bigg)^{2x-1}}\:$

As ,we know that ,

$a^m \times a^n = a ^{m + n}$

$:\implies \sf{ \bigg(\dfrac{11}{9}\bigg)^{3+6} =\bigg(\dfrac{11}{9}\bigg)^{2x-1}}\:$

$:\implies \sf{ \bigg(\dfrac{11}{9}\bigg)^{9} =\bigg(\dfrac{11}{9}\bigg)^{2x-1}}\:$

Therefore :

$:\implies \sf{9 = 2x-1 }\:\\\\:\implies \sf{2x = 9+1 }\:\\\\:\implies \sf{2x = 10 }\:\\\\:\implies \sf{x = \cancel {\dfrac{10}{2}} }\:\\\\\underline {\boxed{\pink{ \mathrm {  x = 5\: }}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {Hence,\:The  \:value \:of\:x \:is\:\bf{5\: }}}}$

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