Math, asked by shriramsain45, 2 months ago

please give me this question answers who give me correct answer I will mark brainliest answer​

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Answers

Answered by dakshinashivani
1

Answer:

Step-by-step explanation:

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Answered by sarala0983
1

Solution: (i) p(x) = 2x3 + x2 – 2x – 1, g(x) = x + 1

Apply remainder theorem

=>x + 1 =0

=> x = - 1

Replace x by – 1 we get

=>2x3 + x2 – 2x – 1

=>2(-1)3 + (-1)2 -2(-1) - 1

=> -2 + 1 + 2 - 1

=> 0

Remainder is 0 so that x+1 is a factor of 2x3 + x2 – 2x – 1

(ii) p(x) = x3 + 3x2 + 3x + 1, g(x) = x + 2

Apply remainder theorem

=>x + 2 =0

=> x = - 2

Replace x by – 2 we get

=>x3 + 3x2 + 3x + 1

=>(-2)3 + 3(-2)2 + 3(-2) + 1

=> -8 + 12 - 6 + 1

=> -1

Remainder is not equal to 0 so that x+2 is not a factor of x3 + 3x2 + 3x + 1

(iii) p(x) = x3 – 4x2 + x + 6, g(x) = x – 3

Apply remainder theorem

=>x - 3 =0

=> x = 3

Replace x by – 2 we get

=>x3 – 4x2 + x + 6

=>(3)3 -4(3)2 + 3 + 6

=> 27 - 36 +3 + 6

=> 0

Remainder is equal to 0 so that x-3 is a factor of x3 – 4x2 + x + 6

3Roman

Solution: (i) p(x) = x2 + x + k

Apply remainder theorem

=>x - 1 =0

=> x = 1

According to remainder theorem p(1) = 0 we get

Plug x = 1 we get

=> k(1)2 + 1+ 1 =0

=>k +1 + 1 =0

=> k + 2 = 0

=> k = - 2

Answer value of k = -2

(ii) p(x) = 2x2 + kx + √2

Apply remainder theorem

=>x - 1 =0

=> x = 1

According to remainder theorem p(1) = 0 we get

Plug x = 1 we get

p(1) = 2(1)2 + k(1) + √2

p(1) =2 + k + √2

0 = 2 + √2 + k

-2 - √2 = k

- (2 + √2) = k

Answer is k = - (2 + √2)

(iii) p(x) = kx2 – √2x + 1

Apply remainder theorem

=>x - 1 =0

=> x = 1

According to remainder theorem p(1) = 0 we get

Plug x = 1 we get

p(1) = k(1)2 – √2(1)+ 1

P(1) = K - √2 + 1

0 = K - √2 + 1

√2 -1 = K

Answer k= √2 -1

(iv) p(x) = kx2 – 3x + k

Apply remainder theorem

=>x - 1 =0

=> x = 1

According to remainder theorem p(1) = 0 we get

Plug x = 1 we get

P(1) = k(1)2 -3(1) + k

0= k – 3 + k

0 = 2k – 3

3 = 2k

3/2 = k

Answer k = 3/2

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