Question

please give Only answers I will make it brain list ans please​

Answer 1

Answer:

hey here is your solution

pls mark it as brainliest

Step-by-step explanation:

so here given quadratic equation is 2x.square-6x+k=0

so it's roots are real and equal

hence discriminant delta=0 (1)

now comparing the given quadratic equation with ax.square+bx+c=0

we get

a=2 b=-6 c=k

so now using

delta=b.square-4ac

ie b.square-4ac=0 from (1)

so substituting values of a,b and c in it

we get

(-6)square-(4×2×k)=0

ie 36-8k=0

so 8k=36

ie k=36/8

hence k=9/2=4.5

hence value of k is 9/2 ie 4.5

Answer 2

Step-by-step explanation:

${2x}^{2} - 6x + k = 0$

Subtract 2x²-6 from both the sides...

${2x}^{2} - 6x + k - ( {2x}^{2} - 6x) = 0 - ( {2x}^{2} - 6)x$

Simplify....

$k = - ( {2x}^{2} - 6x)$

Simplify....

$k = { - 2x}^{2} + 6x$

k = -2x² + 6x is the correct answer

$\huge{ son \: prodigal}$