Question

Please give question on factorization please(0.6a-0.5b)³+(0.5b+0.7c)³-(0.6a +0.7c)³
maths

Answer 1

Answer:

Step-by-step explanation:

Not possible to have ‘two numbers’ whose “HCF is 16 and LCM is 380”.

Solution:

Given: 16 as their ‘HCF’ and 380 as their ‘LCM’.

We know that H.C.F. between the numbers is the ‘highest common factors’ between two numbers while L.C.M. is the ‘lowest common multiple’ of that numbers.

Two numbers with both H.C.F. as 16 and L.C.M. as 380 is not possible. 380 is the L.C.M. must be exactly divisible by 16 as their H.C.F.

But

The answer is in decimal. Thus, L.C.M. 380 is ‘not divisible’ by H.C.F. 16 of two numbers. The given condition is not possible.

Read more on Brainly.in - https://brainly.in/question/538914#readmoreNot possible to have ‘two numbers’ whose “HCF is 16 and LCM is 380”.

Solution:

Given: 16 as their ‘HCF’ and 380 as their ‘LCM’.

We know that H.C.F. between the numbers is the ‘highest common factors’ between two numbers while L.C.M. is the ‘lowest common multiple’ of that numbers.

Two numbers with both H.C.F. as 16 and L.C.M. as 380 is not possible. 380 is the L.C.M. must be exactly divisible by 16 as their H.C.F.

But

The answer is in decimal. Thus, L.C.M. 380 is ‘not divisible’ by H.C.F. 16 of two numbers. The given condition is not possible.

Read more on Brainly.in - https://brainly.in/question/538914#readmoreNot possible to have ‘two numbers’ whose “HCF is 16 and LCM is 380”.

Solution:

J9ZH9+H9

Given: 16 as their ‘HCF’ and 380 as their ‘LCM’.

We know that H.C.F. between the numbers is the ‘highest common factors’ between two numbers while L.C.M. is the ‘lowest common multiple’ of that numbers.

Two numbers with both H.C.F. as 16 and L.C.M. as 380 is not possible. 380 is the L.C.M. must be exactly divisible by 16 as their H.C.F.

But

The answer is in decimal. Thus, L.C.M. 380 is ‘not divisible’ by H.C.F. 16 of two numbers. The given condition is not possible.

Read more on Brainly.in - https://brainly.in/question/538914#readmoreTH

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M86X7+YR7J/7K4+84,

C9+J+JM8F7JF7