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ABCD is a quadrilateral
To prove : ∠AOB=21(∠C+∠D)
AO and BO is bisector of A and B
∠1=∠2∠3=∠4...(1)
∠A+∠B+∠C+∠D=360
(Angle sum property)
21(∠A+∠B+∠C+∠D)=180...(2)
In △AOB
∠1+∠3+∠5=21(∠A+∠B+∠C+∠D)
∠1+∠3+∠5=∠1+∠3+21(∠C+∠D)
∠AOB=21(∠C+∠D)
Hence,Proved.
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The user above me who answered it is correct! Just instead of using Numbers , u should mention the name of the angles then u will get marks in exams. Anyways , good luck!
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