Question

please give solution​

Answer 1

Step-by-step explanation:

given= AB=48 cm

CD=40 cm

to find =distance between the two parallel chords

construction=draw perpendicular from centre to AB At x and ACD at y

join radius from centre to B

joint another radius from centre to D

proof=In triangle PXB

(25)^2-(24)^2=(XP)^2

7=XP

similarly YP=15

XP+XY=distance between chords

7+15=22