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Eq resistance of CD = 1/6+1/6 = 3 ohm
V(battery) = V(AB) = 12V
Now , R(AB) = R(CD)
So , V(AB) = V(CD) = 12/2 = 6V
So , I (CD) = V(CD) / R(CD) = 6/3 = 2A
Current in upper branch and lower branch of CD are same = 1A
V(battery) = V(AB) = 12V
Now , R(AB) = R(CD)
So , V(AB) = V(CD) = 12/2 = 6V
So , I (CD) = V(CD) / R(CD) = 6/3 = 2A
Current in upper branch and lower branch of CD are same = 1A
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