Question

please give solution..............​

Answer 1

Answer:

$\frac{ - c}{d}$

Step-by-step explanation:

$\frac{1}{p} + \frac{1}{q} + \frac{1}{r}$

$cross \: multiply \\ \frac{p + q}{pq} + \frac{1}{r}$

$\frac{pr + qr+pq }{pqr}$

$it \: is \: in \: the \: form \\ \frac{sum \: of \: products \: of \: zeroes}{product \: of \: zeroes}$

$= \frac{ \frac{ c}{a} }{ \frac{ - d}{a} }$

$\frac{ - c}{d}$

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