Question

please give solution...

Answer 1

Answer:

x=1 and y=1

Step-by-step explanation:

let a = 1/(3x+y), b = 1/(3x-y)

The given equation become,

a+b = 3/4

=> a = 3/4 - b ----(1)

and,

a/2 - b/2 = -1/8

=> (a-b)/2 = -1/8

=> a-b = -2/8

=> 3/4-b-b = -2/8 [putting a from (1)]

=> 2b = 1/4+3/4 = 1

=> b = 1/2

=> 1/(3x-y) = 1/2

=> 3x-y = 2

=> y = 3x-2 -----(2)

putting b in (1),

a = 3/4 - b = 3/4 - 1/2 = 1/4

=> 1/(3x+y) = 1/4

=> 3x+y = 4

=> 3x+3x-2 = 4

=> 6x = 4+2 = 6

=> x = 6/6 = 1

putting x in (2),

y = 3x-2 = 3×1-2 =3-2 = 1