please give solution
derive 2 as=u² - v²
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We will use both of the equations of motion to reach the third equation of motion. This will require a bit of algebra.
S=ut+1/ 2at^2andv=u+at, include the time variant t
There will be some situations when we do not have any information about time and so it would be a good idea to derive an equation that does not have a t term.
To do this, we rearrange our first equation to get
t=v−u/a
and use this to replace t wherever it appears in the second equation. So
S=ut+1/ 2at^2
becomes,
S=u(v−u/a )+1/2a( v−u/a )^2
⇒2aS=2u(v−u)+(v−u)^ 2
⇒2aS=2uv−2u^2 −v^2 −2uv−u^2
⇒2aS=v^ 2 −u^2
⇒v^2 =u^2 +2aS
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