PLEASE give solution for Question 21-29
Attachments:
Answers
Answered by
2
Given Mass = 0.09g
The molar mass of water is 18g/m
We know that,
Mass= moles × molar mass
Or, Moles = Mass/ Molar mass
or, Moles = 0.09/ 18
or, Moles = 0.005
Again,
1 mole of any particle contains 6.022 × 10^23
0.005 mole of any particle contains 6.022 × 10^23 × 0.005 or, 3.011 × 10^21
___________________________________
2) The molecular mass of S8 is 256g/m
Mass = Moles × molar mass
or,Moles = Mass/ molar mass
or, Moles= 5.12 / 256
or, Moles = 0.02
0.02 moles of Sulfur are present.
Now,
The number of Sulfur molecules = Number of moles × Avogadro number
Or, The number of Sulfur molecules = 0.02 × 6.022 × 10^23 or, 1.204 × 10^22
The number of atoms in Sulfur = 1.50 × 10^ 23 × 8 or, 1.2 × 10^24
___________________________________
3)The molar mass of Phosphorus = 124g/m
Mass = Moles × Molar mass
or, Moles = Mass /Molar mass
or, Molar mass = 100/124
or, Molar mass = 0.8
Number of moles = 6.022 × 10^23 × 0.8 or, 4.81 × 10^23
____________________________________
5) 1 mole of carbon contains 12 g carbon.
12 g carbon has 6.022 × 10^23 carbon atoms
So, 10^-12 g carbon has 6.022 × 10^23/12 × 10^-12 or 5.02 × 10^10 carbon atoms.
___________________________________
6) Given,
Density = 3 g/lit
Temperature = 273°c or, 546K
Pressure = 1140 mmHg or 1.5 atm
We know,
Density = Mass / Volume
3 = Mass / 1
or, Mass = 3 g
According to Ideal Gas law,
PV = nRT
or, PV = m/M RT [ as we know Mass= Moles × molar mass]
or, 1.5 × 1 = 3 /M × 0.082 × 546
or, 1.5 = 3/ M × 0.082 × 546
or, 1.5M = 134.3
or, M = 134.3/ 1.5
or, M= 89.5g/m
____________________________________
6) Molecular Mass of Suger=342g/ m
Given,
the cost of 1000g suger [as 1kg =1000g] is 40
the cost of 342g suger is 40/ 1000× 342 or,₹ 13.68
So the cost per mole is ₹13.68
___________________________________
7)I think the answer should be 2 g of Nitrogen weights the least.
___________________________________
8)The Molecular Mass of Caustic Soda is 40g/m
40g NaOH contains 6.022×10^23 particles
4 g of NaOH contains 6.022× 10^23/40× 4 or, 6.02×10^22
___________________________________
Hope it helps
The molar mass of water is 18g/m
We know that,
Mass= moles × molar mass
Or, Moles = Mass/ Molar mass
or, Moles = 0.09/ 18
or, Moles = 0.005
Again,
1 mole of any particle contains 6.022 × 10^23
0.005 mole of any particle contains 6.022 × 10^23 × 0.005 or, 3.011 × 10^21
___________________________________
2) The molecular mass of S8 is 256g/m
Mass = Moles × molar mass
or,Moles = Mass/ molar mass
or, Moles= 5.12 / 256
or, Moles = 0.02
0.02 moles of Sulfur are present.
Now,
The number of Sulfur molecules = Number of moles × Avogadro number
Or, The number of Sulfur molecules = 0.02 × 6.022 × 10^23 or, 1.204 × 10^22
The number of atoms in Sulfur = 1.50 × 10^ 23 × 8 or, 1.2 × 10^24
___________________________________
3)The molar mass of Phosphorus = 124g/m
Mass = Moles × Molar mass
or, Moles = Mass /Molar mass
or, Molar mass = 100/124
or, Molar mass = 0.8
Number of moles = 6.022 × 10^23 × 0.8 or, 4.81 × 10^23
____________________________________
5) 1 mole of carbon contains 12 g carbon.
12 g carbon has 6.022 × 10^23 carbon atoms
So, 10^-12 g carbon has 6.022 × 10^23/12 × 10^-12 or 5.02 × 10^10 carbon atoms.
___________________________________
6) Given,
Density = 3 g/lit
Temperature = 273°c or, 546K
Pressure = 1140 mmHg or 1.5 atm
We know,
Density = Mass / Volume
3 = Mass / 1
or, Mass = 3 g
According to Ideal Gas law,
PV = nRT
or, PV = m/M RT [ as we know Mass= Moles × molar mass]
or, 1.5 × 1 = 3 /M × 0.082 × 546
or, 1.5 = 3/ M × 0.082 × 546
or, 1.5M = 134.3
or, M = 134.3/ 1.5
or, M= 89.5g/m
____________________________________
6) Molecular Mass of Suger=342g/ m
Given,
the cost of 1000g suger [as 1kg =1000g] is 40
the cost of 342g suger is 40/ 1000× 342 or,₹ 13.68
So the cost per mole is ₹13.68
___________________________________
7)I think the answer should be 2 g of Nitrogen weights the least.
___________________________________
8)The Molecular Mass of Caustic Soda is 40g/m
40g NaOH contains 6.022×10^23 particles
4 g of NaOH contains 6.022× 10^23/40× 4 or, 6.02×10^22
___________________________________
Hope it helps
abhi178:
Good answering
Similar questions