Please give step by step explaintion for this question. If you don't know don't give answer
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angle a+ angle b= angle C {alternate angles}
angle a+ angle b= angle C {alternate angles}angle a + angle b= 57°
angle a= C/3 - GIVEN
c/3 + angle b= 57°
c/3 + angle b= 57°57/3 + angle b= 57°
c/3 + angle b= 57°57/3 + angle b= 57°angle b= 57- 57/3
c/3 + angle b= 57°57/3 + angle b= 57°angle b= 57- 57/3angle b= 57 - 19= 38°
angle b+ angle d= 180° {linear pair}
angle d= 180 - 38= 142°
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Answer:
Your answer is 142
Step-by-step explanation:
- Given that PQ, RS, UT are parallel
- C = 57
- a = c/3 it means 57/3 = 19
- a + b = 180 ( linear pair)
- 19 + b = 180 , b = 161
- Now b + d = a ( by external angle theorem )
- we have b = 161 + d = 19
- Now d = 161 - 19 = 142
- The value of d is 142
Note : The external angle theorem says that the sum of two internal angles is equal to the sum of the external angle
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