Question

please give the answer ​

Answer 1

sorry I didn't know the answer to your questions

Answer 2

Answer:

-12+√6

Step-by-step explanation:

$\frac{-2\sqrt{3} }{\sqrt{3} -\sqrt{2} } +\frac{3\sqrt{2} }{\sqrt{3} +\sqrt{2} }$

Using the identity $(a+b)(a-b)=a^2-b^2$, it can be simplified.

$-\frac{2\sqrt{3}(\sqrt{3} +\sqrt{2} ) }{3-2} +\frac{3\sqrt{2} (\sqrt{3} -\sqrt{2} )}{3-2}$

$=-2\sqrt{3}(\sqrt{3} +\sqrt{2} )+3\sqrt{2} (\sqrt{3} -\sqrt{2} )$

$=-6-2\sqrt{6} +3\sqrt{6} -6$

$=-12+\sqrt{6}$

∴-12+√6