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Answers
▶ Solution :
Given :
A farmer moves along the boundary of a square field of side 10m in 40s.
To Find :
Magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position.
Concept :
▪ Displacement is defined as the shortest distance b/w initial and final point of whole journey.
▪ Displacement is a vector quantity.
▪ Displacement can be positive, negative and zero.
Calculation :
✏ 2min 20sec = 140sec = (120+20)sec
✏ Farmer will cover 3(1/2) round of square after the given time.
✏ As per definition of displacement,
▪ Displacement = Δposition
▪ Displacement = √2(side)
▪ Displacement = √2(10)
▪ Displacement = 10√2m
✴ Displacement can be zero. (i.e. returns to the initial position)
✴ Distance is defined as the total actual length of path which is covered by moving body.
✴ Relation between distance(path length) and displacement is given by
Distance Displacement
Gɪᴠᴇɴ
➤ A farmer moves along the boundary of a square field of side 10m in 40s.
_________________
ᴛᴏ ꜰɪɴᴅ
✪ Magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position.
_________________
Sᴛᴇᴘꜱ
Calculation :
☞ 2min 20sec = 140sec = (120+20)sec
☞ Farmer will cover 3(1/2) round of square after the given time.
☞ As per definition of displacement,
▪ Displacement = Δposition
▪ Displacement = √2(side)
▪ Displacement = √2(10)
▪ Displacement = 10√2m
✴ Displacement can be zero. (i.e. returns to the initial position)
✴ Distance is defined as the total actual length of path which is covered by moving body.
✴ Relation between distance(path length) and displacement is given by
Distance \geqslant⩾ Displacement
➜
❍ Displacement is defined as the shortest distance b/w initial and final point of whole journey.
❍ Displacement is a vector quantity.
❍ Displacement can be positive, negative and zero.