Question

please give the answer​

Answer 1

Answer:

1. A body is said to be in uniform acceleration when it is increasing its speed equally in equal intervals of time. A body is said to be in non uniform acceleration when it is increasing unequal amount of speed in equal intervals of time.

2. Acceleration a = (V - U) / t

Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.2m/sec

            Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.6m/sec

Acceleration a = (V - U) / t

                        = (16.6 - 22.2)/5

                        = -5.6/5

                        = -1.12 m/s2

Negative sign indicates that the velocity is decreasing.

Therefore, the acceleration of the bus that decreases its speed from 80 kilometers per hour to 60 km per hour in 5 seconds is -1.12m/s2

3. Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.)

Final speed of the train, v = 40 km/h = \frac{5}{18}185 × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ a=\frac{v-u}{t}a=tv−u

Solution:-

Putting all the values, we get

⇒ a=\frac{v-u}{t}a=tv−u

⇒ a=\frac{11.11-0}{600}a=60011.11−0

⇒ a=\frac{11.11}{600}a=60011.11

⇒ a=0.0185 \: m/s^2a=0.0185m/s2

Hence, Acceleration of the train is 0.0185 m/s².

Answer 2

Explanation:

1. a body is said to be in uniform acceleration if the body moves in a straight line and the velocity is increasing or decreasing in equal amounts in equal interval of time

(ii) a body is said to be in non-uniform acceleration if the rate of change of velocity of the body is not constant.

2. we know that v = u + at

here u= 80km/hr

v= 60km/hr

t = 5s

by putting the formula we get -

60km/hr = 80km/hr + a X 5s

= -20km/hr = a X 5s

= we have to change -20km/hr into metre per second so, we have to multiply 5/18 to -20 so we get, = -20X 5/18 = -50/9m/s

= -50/9 m/second = a X 5 s

= so a = -50/9 X 1/5 = -10/9 m/s² ans

3. here u = 0km/hr

v = 40km/hr

t = 10minute

= v = u + at

= 40km/hr = 0km/hr + a X 10 minute

= 40000/60 = aX 10

so a = 40000/60 X 1/10 = 200/3 m/s² ans

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