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figure a
in ∆abc
a+b+c=180°. ( by angle sum property )
angle a = 180°-122°. ( by linear pair )
a = 58°
angle b = 180°-128° . ( by linear pair )
b = 52°
angle c we can easily calculate by angle sum property .
58° + 52° + c = 180°.
c = 180- 110°
c = 70°
then ,
x = 180° - 70° ( by linear pair )
x = 110°
answer of figure 2
angle a = 180° - 160°= 20° ( by linear pair )
angle c = 110°
angle b = ( 180°- a+b ) 180- 20°+110° ( by angle sum property )
b = 50°
then we can easily calculate the value of x by linear pair .
x = 180°-50°
x = 130°
i hope you get your answer .
thank you !!
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