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a+(m-1)d=1/n.....(i)
a+(n-1)d=1/m.....(ii)
subtracting both
d(m-1+1-n)=(m-n)/mn
d=1/mn
putting the value of d in 1
a=1/n-(m-1)/mn
a=m-m+1/mn
a=1/mn
atq
a+(mn-1)d
1/mn+(mn-1)/mn
(1+mn-1)/mn
mn/mn
1=RHS proved
a+(n-1)d=1/m.....(ii)
subtracting both
d(m-1+1-n)=(m-n)/mn
d=1/mn
putting the value of d in 1
a=1/n-(m-1)/mn
a=m-m+1/mn
a=1/mn
atq
a+(mn-1)d
1/mn+(mn-1)/mn
(1+mn-1)/mn
mn/mn
1=RHS proved
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