Math, asked by pranav775, 5 months ago

Please give the answer fast​

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Answers

Answered by vipashyana1
0

Answer:

 \frac{ \frac{1}{4}  +  \frac{1}{4} \div 1 \frac{1}{4}  }{ \frac{1}{4}  \times  \frac{1}{4} + 2 \frac{1}{4}  }  =  \frac{74}{80}

Step-by-step explanation:

 \frac{ \frac{1}{4}  +  \frac{1}{4} \div 1 \frac{1}{4}  }{ \frac{1}{4}  \times  \frac{1}{4} + 2 \frac{1}{4}  }

 =  \frac{ \frac{1 + 1}{4}  \times  \frac{4}{5} }{ \frac{1}{16}  +  \frac{9}{4} }

 = \frac{ \frac{2}{4} \times  \frac{4}{5}  }{ \frac{1 + 36}{16} }

 =  \frac{ \frac{2}{5} }{ \frac{37}{16} }

 =  \frac{2}{5}  \times  \frac{37}{16}

 =  \frac{74}{80}

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