Chemistry, asked by varsha88811, 10 months ago

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Answered by Anonymous
1

(a) Ethyne (C_2H_2C2H2) = 2\times Mass\ of\ C \ atom+2\times Mass\ of\ H\ atom=2\times 12+2\times 1=24+2=26\ g/mol2×Mass of C atom+2×Mass of H atom=2×12+2×1=24+2=26 g/mol

(b) Sulphur dioxide (S_8S8)=8\times Mass\ of\ sulphur\ atom=8\times 32=256\ g/mol8×Mass of sulphur atom=8×32=256 g/mol

(c) P_4=4\times Mass\ of\ P\ atom=4\times 31=124\ g/molP4=4×Mass of P atom=4×31=124 g/mol

(d) HCl=1\times Mass\ of\ H\ atom+1\times Mass\ of\ Cl\ atom=1+35.5=36.5\ g/molHCl=1×Mass of H atom+1×Mass of Cl atom=1+35.5=36.5 g/mol

(e) HNO_3=1\times Mass\ of\ H\ atom + 1\times Mass\ of\ N\ atom+ 3\times Mass\ of\ O\ atomHNO3=1×Mass of H atom+1×Mass of N atom+3×Mass of O atom</p><p></p><p>=1\times1+1\times 14+3\times16=63\ g/mol=1×1+1×14+3×16=63 g/mol

Answered by Anonymous
1

Answer:

Ethyne (C_2H_2C  

2

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H  

2

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) = 2\times Mass\ of\ C \ atom+2\times Mass\ of\ H\ atom=2\times 12+2\times 1=24+2=26\ g/mol2×Mass of C atom+2×Mass of H atom=2×12+2×1=24+2=26 g/mol

(b) Sulphur dioxide (S_8S  

8

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)=8\times Mass\ of\ sulphur\ atom=8\times 32=256\ g/mol8×Mass of sulphur atom=8×32=256 g/mol

(c) P_4=4\times Mass\ of\ P\ atom=4\times 31=124\ g/molP  

4

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=4×Mass of P atom=4×31=124 g/mol

(d) HCl=1\times Mass\ of\ H\ atom+1\times Mass\ of\ Cl\ atom=1+35.5=36.5\ g/molHCl=1×Mass of H atom+1×Mass of Cl atom=1+35.5=36.5 g/mol

(e) HNO_3=1\times Mass\ of\ H\ atom + 1\times Mass\ of\ N\ atom+ 3\times Mass\ of\ O\ atomHNO  

3

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=1×Mass of H atom+1×Mass of N atom+3×Mass of O atom

=1\times1+1\times 14+3\times16=63\ g/mol=1×1+1×14+3×16=63 g/mol

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