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the one who joined the team is tallest.he is height of 180.5 cm
akash8930:
galat hai bhai
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let the ∑ of remaining members height be 4x
avh₁=181
avh₂=181+1.5=182.5
(4x+y₁)/5=181
4x+y₁=905
4x=905-y₁.....(1)
(4x+y₂)/5=182.5
4x+y₂=912.5
4x=912.5-y₂......(2)
equating (1) and (2)
905-y₁=912.5-y₂
y₂-y₁=7.5......(3)
y₂>y₁
the new player is longer.
now putting y₂=179 in(3)
y₁=179-7.5
y₁=171.5cm
putting y₁=179 in(3)
y₂=179+7.5
y₂= 186.5 cm
avh₁=181
avh₂=181+1.5=182.5
(4x+y₁)/5=181
4x+y₁=905
4x=905-y₁.....(1)
(4x+y₂)/5=182.5
4x+y₂=912.5
4x=912.5-y₂......(2)
equating (1) and (2)
905-y₁=912.5-y₂
y₂-y₁=7.5......(3)
y₂>y₁
the new player is longer.
now putting y₂=179 in(3)
y₁=179-7.5
y₁=171.5cm
putting y₁=179 in(3)
y₂=179+7.5
y₂= 186.5 cm
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