Please give the answer in image...the right answer will be marked as brainlist..And don't spam please..
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Perimeter of a triangle = sum of all sides of triangle
given sides= (4x+2y+z) , (3x+7y-2z)
then perimeter = 4x+2y+z+3x+7y-2z+third side= -3x+4y+2z
7x+9y-z+ third side=-3x+7y-2z
third side = -10x -2y -z
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Thanks siso...
but ab bas bhi kro mujhe itne thanks nhii chaiye
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