Question

Please give the answer of any of these questions. I will mark you "Brainliest" if answers of all the are given. ​

Answer 1

Answer:

20.solution

Step-by-step explanation:

Cosec =1/sin

Sec =1/cos

So,taking lHS we get...

(1/sinA-sinA)(1/cosA-cosA)

=(1-sin sq A/sin A) (1-cos sq A/cos A)

=(cosSqA /sin A) (sin sqA /cos A)

= 1/Tan A + cot A

Answer 2

Answer:

Step-by-step explanation:

Q18,20. sec²x - tan²x = 1

a² - b² = (a - b)(a + b)

Q19. sin²A + cos²A = 1

~~~~~~~~~