Question

please give the answer of both fast ​

Answer 1

Answer:

B)-6,c)c/a

Step-by-step explanation:

1) as if 1 is a root then we can simply put 1 in

the quadratic polynomial hece we will get

1^2 +5×1+k =0

1+5+k =0

K=-6

Now

For 2) if its two zeroes is 0

Then put 0 in the polynomial hence we get

0+0+0+d=0

so d=0

Now polynomial is ax^3+bx^2+cx+0 =0

Now we can take x as common

x(ax^2+bx+c)=0

From here we get x=0

Hence

ax^2+bx+c=0 has two zeroes one is 0 and second is not known so we can simply put 0 in the polynomial ax^2 +bx+c=0

Hence we get 0 +0 +c=0

So c=0

Now we get the polynomial as ax^2+bx=0

Now again take x common hence we get x(ax+b)=0

Now x =0 ,ax+b=0

So x=-b/a

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