Please give the answer of given Q in picture.
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Answer:3√3
Step-by-step explanation
join the centre and the external point
let this line formed be OP
and the tangents be PA and PB
Now,∠APB=60°
∴∠APO=1/2∠APB=30°
tan30°=OA/PA
1/√3 = radius/PA
PA=radius*√3
PA=3√3
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