please give the answer of question 8
Answers
Hi!
Here's your ans..
STEP BY STEP EXPLANATION:~
i) No.of electrons present in X
= No. of protons present in X
=Atomic no. of X
=7
therefore acc. to Bhor's atomic law..
No. of electrons which can be accommodated in first K shell= 2
No. of electrons which can be accommodated in second L shell=8
Now, total no. of electrons=7
Thus,no. of electrons in K shell= 2
& no. of electrons in L shell=(7-2)=5
Hence the elctronic configuration of X is 2,5 .
ii) Acc. to i)
electronic configuration of X is 2,5.
No. of electrons present outermost L shell or valence shell = 5
Total no. electrons which can be actually accomodated in L shell =8(acc. to Bohr's
atomic law)
So to achieve its nearest elctronic configuration it will gain (8-5)=3 electrons... Hence the valency of X is +3.
iii) No. of protons =Atomic No.=7
No. of neutrons= Mass No. - Atomic No.
=14 - 7
=7
iv) 14 represents the Mass No.(No.of protons+No. of neutrons)of X &
7 represents Atomic No. of X i.e. No.of protons.
Hope it helps..