Please give the answer of this
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By substituting values of n, the elements in the range of function are,
{1, 2, 3, 4, 5, 6,
...}, i.e. set of all natural number So the range and co-domain are same, ergo function is onto. Also f(1) = f(2), so the function is many one.
Hence the given function is many one and onto
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